2(3x^2+2)=2(x^2+4)

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Solution for 2(3x^2+2)=2(x^2+4) equation:


Simplifying
2(3x2 + 2) = 2(x2 + 4)

Reorder the terms:
2(2 + 3x2) = 2(x2 + 4)
(2 * 2 + 3x2 * 2) = 2(x2 + 4)
(4 + 6x2) = 2(x2 + 4)

Reorder the terms:
4 + 6x2 = 2(4 + x2)
4 + 6x2 = (4 * 2 + x2 * 2)
4 + 6x2 = (8 + 2x2)

Solving
4 + 6x2 = 8 + 2x2

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-2x2' to each side of the equation.
4 + 6x2 + -2x2 = 8 + 2x2 + -2x2

Combine like terms: 6x2 + -2x2 = 4x2
4 + 4x2 = 8 + 2x2 + -2x2

Combine like terms: 2x2 + -2x2 = 0
4 + 4x2 = 8 + 0
4 + 4x2 = 8

Add '-4' to each side of the equation.
4 + -4 + 4x2 = 8 + -4

Combine like terms: 4 + -4 = 0
0 + 4x2 = 8 + -4
4x2 = 8 + -4

Combine like terms: 8 + -4 = 4
4x2 = 4

Divide each side by '4'.
x2 = 1

Simplifying
x2 = 1

Take the square root of each side:
x = {-1, 1}

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